1 .	Find the smallest number which when divided by 25, 40 or 56 has in each case 13 as remainder.
[ A ]    1413 [ B ]    1400 [ C ]    1439 [ D ]    1426
Answer : Option A Explanation : L C M of 25, 40, 56 $\begin{array}{c|lcr} 2& \text{25}, & \text{40}, & \text{56} \\ \hline 5 & 25, & 20, & 28 \\\hline 2 & 5, & 4, & 28 \\\hline 2 & 5, & 2, & 14\\\hline & 5, & 1, & 7 \end{array}$ = 2 × 5 × 2 × 2 × 5 × 7 = 1400 Smallest Number = 1400 + 13 = 1413.
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