1 .	If A and B are complementary angles, then the value of sin A cos B + cos A sin B – tan A tan B + $sec^2$ A – $cot^2$ B is–
[ A ]    1 [ B ]    -1 [ C ]    2 [ D ]    0
Answer : Option A Explanation : sin A cos B + cos A sin B – tan A tan B + $sec^2$ A – $cot^2$ B = sinA sin A + cosA cosA – tanA. cot A + $sec^2$ A – $tan^2$ B = ($sec^2$ A + $cot^2$ A) – 1 + (1) = 1 – 1 + 1 = 1
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