| 1 . |
If 3y + $1 \over 2y$ = 4, then the value of $3y \over 3y(2y + 7) + 28y +1$ is |
|
|
Answer & Explanation
| Answer : Option B |
|
| Explanation : |
|
 |
|
|
|
|
|
|
|
|
|
| 2 . |
Find the greatest four-digit number which when divided by 3, 9, 12, 21 and 24 leaves the same remainder 2 in each case |
|
|
Answer & Explanation
| Answer : Option C |
|
| Explanation : |
|
LCM of 3,9,12,21,24 = 504
Now, greatest number of four digits = 9999
When 9999 is divided by 504 , the remainer is 423.
Hence , the greatest number of four digits exactly divisible by each of the numbers 3,9,12,21 abd
24=9999-423=9576
So Reqd no.= 9576 + 2=9578. |
|
|
|
|
|
|
|
|
|
| 3 . |
24 mango trees, 48 apple trees and 64 orange trees have to be planted in rows such that each row contains the same number of trees of one variety only. The minimum number of rows in which the above trees can be planted is |
|
|
Answer & Explanation
| Answer : Option A |
|
| Explanation : |
|
HCF of 24 , 48 and 64 = 8
$24\over 8$ = 3, $48 \over 8$ = 6 and $64 \over 8$ = 8
So Required number of rows =( 3+ 6 + 8) = 17 |
|
|
|
|
|
|
|
|
|
| 4 . |
A and B invest in a business in the ratio 7 : 6. If 15% of the total profit goes to charity and B's profit share is Rs. 6300, the total approximate profit is (Rs.) |
|
|
Answer & Explanation
| Answer : Option D |
|
| Explanation : |
|
Let the share of profit of A
be 7x and B be 6x. Then, 6x=6300
So x = $6300 \over 6$ = Rs. 1050
Now A's share in the profit = 7 x 1050= 7350
Total profit earned by A and B =
7350 + 6300 = Rs 13650
Remaining profit = (100 - 15 )= 85%
So, 100% = $13650 \times 100 \over 85$ = 16058.82 $\cong$16060 |
|
|
|
|
|
|
|
|
|
| 5 . |
If $8^{126}$is divided by 63, the remainder will be |
|
|
Answer & Explanation
| Answer : Option C |
|
| Explanation : |
|
 |
|
|
|
|
|
|
|
|
|
| 6 . |
Which of the following numbers does not fit into the series?
13 20 34 63 118 230 |
|
|
Answer & Explanation
| Answer : Option B |
|
| Explanation : |
|
| The series is +7,+14,+28,+56,+112 |
|
|
|
|
|
|
|
|
|
| 7 . |
The length of rectangle is twice its breadth. If its length is decreased by 8 cm and breadth is increased by 8 cm, the area of the rectangle is increased by 64 $cm^2$. The length of the rectangle is |
|
|
Answer & Explanation
| Answer : Option C |
|
| Explanation : |
|
Let the breadth be x.
Then length = 2x
Now , (x+8) (2x-8)-X x 2x =64
Or $2x^2$+ 16x - 8x -64 - $2x^2$=64
Or, 8x = 64 +64=128
Or, x = = 16 cm
So, length = 2x = 2x 16 =32 cm |
|
|
|
|
|
|
|
|
|
| 8 . |
If $x^2$ + $1 \over x^2$ = 51, find the value of $x^3$ - $1 \over x^3$ |
|
|
Answer & Explanation
| Answer : Option C |
|
| Explanation : |
|
 |
|
|
|
|
|
|
|
|
|
| 9 . |
If three medians PQ, RS and MN of PRM meet at O as shown in the given figure, which of the following statements is not correct?
 |
|
|
Answer & Explanation
| Answer : Option D |
|
| Explanation : |
|
|
|
|
|
|
|
|
|
|
|
| 10 . |
If sin$\theta$ = $3 \over 5$, then the valueof $2 sec \theta \over 1 + tan\theta$ is |
|
|
Answer & Explanation
| Answer : Option B |
|
| Explanation : |
|
 |
|
|
|
|
|
|
|
|
|
|
