A man walks at the speed of 5 km/hr and runs at the speed of 10 km/hr. How much time will the man require to cover the distance of 28 km, if he covers half (first 14 km) of his journey walking and half of his journey running ?
Answer : Option D
Explanation :
Total time required = $14\over5$ +$14\over10$
= $28+14\over10$ + = 4.2 hrs
