P and Q are two points observed from the top of a builing 10$\sqrt3$ m high. If the angles of depressi on of t he poi nts are complementary and PQ = 20 m, then the distance of P from the building is –
sin A cos B + cos A sin B – tan A tan B
+ $sec^2$ A – $cot^2$ B
= sinA sin A + cosA cosA – tanA. cot A
+ $sec^2$ A – $tan^2$ B
= ($sec^2$ A + $cot^2$ A) – 1 + (1)
= 1 – 1 + 1
= 1
A, O, B are three points on a line segment and C is a point not lying on AOB. If ∠AOC = 40° and OX, OY are the internal and external bisectors of ∠ AOC respectively, then ∠ BOY is –