Question no 1910 SSC CHSL Quantitative Aptitude Questions and Answers Free Online Test 1

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1 .

The maximum value of F in the following equation 5E9 + 2F8 + 3G7 = 1114 where E, F, G each is stands for any digit ?

[ A ] 8
[ B ] 7
[ C ] 9
[ D ] 5

Answer : Option C

Explanation :

5E9 + 2F8 + 3G7 = 1114
500 + 10 × E + 9 + 200 + 10 × F + 8 + 300 +
10 × G + 7 = 1114
10E + 10F + 10G = 1114 – (9 + 8 + 7) – (500 + 200 + 300)
10E + 10F + 10G = 90
E + F + G = 9
So, the maximum value of F can be 9.

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