Question no 1752 SSC CGL Tier 1 Quantitative Aptitude Questions and Answers Free Online Mock Test 43

SSC CGL Tier 1 :: QA Test 43

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1 .

Provided, sin(A – B) = sinA cosB – cosA sinB, then sin15° will be
A.$\sqrt3-3\over2\sqrt3$
B.$\sqrt3-3\over\sqrt2$
C.$\sqrt3\over2\sqrt2$
D.$\sqrt3+3\over2\sqrt3$

[ A ] a
[ B ] b
[ C ] c
[ D ] d

Answer : Option A

Explanation :

sin (15º) = sin (45º – 30º)
= sin 45º cos30º – cos30º sin 45º
= $1\over\sqrt2$ x $\sqrt3\over2$ - $1\over2$x $1\over\sqrt2$
= $\sqrt3-1\over2\sqrt2$

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