| [ A ] 133100 |
|
| [ B ] 121000 | ![]() |
| [ C ] 120000 | |
| [ D ] 110000 |
| [ A ] 133100 |
|
| [ B ] 121000 | ![]() |
| [ C ] 120000 | |
| [ D ] 110000 |
| Answer : Option B |
| Explanation : |
| Population at the starting of third year = 100000 $[1 + $10 \over 100$]^2$ = 121000 |
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