[ A ] 133100 |
|
[ B ] 121000 | ![]() |
[ C ] 120000 | |
[ D ] 110000 |
[ A ] 133100 |
|
[ B ] 121000 | ![]() |
[ C ] 120000 | |
[ D ] 110000 |
Answer : Option B |
Explanation : |
Population at the starting of third year = 100000 $[1 + $10 \over 100$]^2$ = 121000 |
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