1 . The radi us of cross-se ct ion of a sol id cyl indric al rod of iron is 50 cm. The cylinder is melted down and formed in to six solid spherical balls of the same radius as that of the cylinder. The length of the rod (in meters) will be –
A.  0.8
B.  2
C.  3
D.  4
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2 . If the base of a right pyramid is a triangle of sides 5 cm, 12 cm, 13 cm and its volume is 330 cm 3 , then its height will be –
A.  33 cm
B.  32 cm
C.  11 cm
D.  22 cm
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3 . The sum of two numbers is 520. If the bigger number is decreased by 4% and the smaller number is increased by 12%, then the numbers obtained are equal. The smaller number is –
A.  280
B.  210
C.  240
D.  260
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4 . Arbind spends 75% of his income and saves the rest. His income is increased by 20% and he increased his expenditure by 10%. Then the increase in savings in percentage is –
A.  55%
B.  52%
C.  50%
D.  48%
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5 . Two alloys are made up of both copper and tin. The ratio of copper and tin in the first alloy is 1 : 3 and in the second alloy is 2 : 5. In what ratio should the two alloys be mixed, to obtain a new alloy in which the ratio of tin and copper be 8 : 3 ?
A.  3 : 5
B.  4 : 7
C.  3 : 8
D.  5 : 11
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6 . The elevation of the top of a tower from a point on the ground is 45°. On travelling 60 m from the point towards the tower the elevation of the top becomes 60°. The height of the tower is –
A.  30 m
B.  30(3-$\sqrt3$) m
C.  30(3+$\sqrt3$) m
D.  30$\sqrt3$ m
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7 . 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m 3 , then the rise in the water level in the tank will be –
A.  20 cm
B.  25 cm
C.  35 cm
D.  50 cm
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8 . The curved surface area of a cylindrical pillar is 264 m 2 and its volume is 924 m 3 . Find the ratio of its diameter to its height
A.  3 : 7
B.  7 : 3
C.  6 : 7
D.  7 : 6
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9 . How many bricks each measuring 25 cm × 11.25 cm × 6 cm, will be needed to build a wall of 8 m × 6 m × 22.5 cm ?
A.  5600
B.  6000
C.  6400
D.  7200
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10 . Find the value of $(secA × cotA)^2$ – $(cosec A × cosA)^2$
$(secA × cotA)^2$ – $(cosec A × cosA)^2$
A.  0
B.  1
C.  2
D.  3
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