First number = 8 and the sum of the digits of the second number is 2 + 8 = 10.
Thus the difference of the first number and the sum of the digits of second number is 10 - 8 = 2.
Similarly, the sum of the digits of third number is 2 + 7 = 9.
Hence the sum of digits of fourth number should be 2 more than 9 i.e. 11 and 6 + 5 = 11
Hence, (d) 65 is the correct option
JQDKB : The order of the letters of the first group is reversed and each letter is moved one step backward to obtain the correspondin letters of the second group.
The first and third letters of the first group are each moved two steps forward, and the second and fourth letters are each moved two steps backward to obtain the corresponding letters of the second group