First number = 8 and the sum of the digits of the second
number is 2 + 8 = 10.
Thus the difference of the first number and the sum of
the digits of second number is 10 - 8 = 2.
Similarly, the sum of the digits of third number is 2 + 7
= 9.

Hence the sum of digits of fourth number should be 2
more than 9 i.e. 11 and 6 + 5 = 11
Hence, (d) 65 is the correct option

JQDKB : The order of the letters of the first group is
reversed and each letter is moved one step backward
to obtain the correspondin letters of the second group.

The first and third letters of the first group are each
moved two steps forward, and the second and fourth
letters are each moved two steps backward to obtain
the corresponding letters of the second group