# ssc cgl tier 1 :: quantitative aptitude :: qa test 60 ## Home ssc cgl tier 1 / quantitative aptitude Questions and Answers

1 .
If 3y + $1 \over 2y$ = 4, then the value of $3y \over 3y(2y + 7) + 28y +1$ is
$3 \over 19$
$1 \over 19$
$1 \over 57$
$1 \over 6$ View Answer Discuss in Forum

2 .
Find the greatest four-digit number which when divided by 3, 9, 12, 21 and 24 leaves the same remainder 2 in each case
9978
9576
9578
9958 View Answer Discuss in Forum

3 .
24 mango trees, 48 apple trees and 64 orange trees have to be planted in rows such that each row contains the same number of trees of one variety only. The minimum number of rows in which the above trees can be planted is
17
8
24
Cannot be determined View Answer Discuss in Forum

4 .
A and B invest in a business in the ratio 7 : 6. If 15% of the total profit goes to charity and B's profit share is Rs. 6300, the total approximate profit is (Rs.)
15000 Rs.
17000 Rs
15060 Rs
16060 Rs. View Answer Discuss in Forum

5 .
If $8^{126}$is divided by 63, the remainder will be
2
5
1
3 View Answer Discuss in Forum

6 .
Which of the following numbers does not fit into the series?

13 20 34 63 118 230
34
63
20
13 View Answer Discuss in Forum

7 .
The length of rectangle is twice its breadth. If its length is decreased by 8 cm and breadth is increased by 8 cm, the area of the rectangle is increased by 64 $cm^2$. The length of the rectangle is
24 cm
16 cm
32 cm
12 cm View Answer Discuss in Forum

8 .
If $x^2$ + $1 \over x^2$ = 51, find the value of $x^3$ - $1 \over x^3$
7
343
364
264 View Answer Discuss in Forum

9 .
If three medians PQ, RS and MN of PRM meet at O as shown in the given figure, which of the following statements is not correct? Area OPM = Area OMR = Area OPR
2 NO = OM
Area OSM = $1\over 6$ Area PRM
The perpendiculars drawn from O to the three sides of $\Delta$ PRM are of equal length View Answer Discuss in Forum

10 .
If sin$\theta$ = $3 \over 5$, then the valueof $2 sec \theta \over 1 + tan\theta$ is
$7 \over 10$
$10 \over 7$
$1 \over 7$
$5 \over 7$ View Answer Discuss in Forum