1 .
Joe root scores 180 runs in first test match. In second test match his run increased to 5 : 6 from first match and in third test match his run decreased to 4 : 3 from second match. Find his average runs in all the matches
Answer & Explanation
Answer : Option A 

Explanation : 

Runs in the first match = 180
Runs in the second match = $180 \over 5$ $\times$ 6 = 216
Runs in the third match = $216 \over 4$ $\times$ 3 = 162
Required average = $180 + 216 + 162 \over 3$ = 186 
2 .
Find the LCM of $2^ 2 $ $\times$ $3^ 2 $ $\times$$ 5^ 2$ , 2 $\times$$ 3^ 3 $ $\times$ $5^ 2 $ , 2 $\times$$ 3^ 2 $ $\times$ 5
Answer & Explanation
Answer : Option A 

Explanation : 

Required LCM = $2^ 2$ $\times$ $3^ 3$ $\times$ $5^ 2$ 
3 .
Two candles of same height are lit together at the same time. First candle takes 10 hrs, while second takes 9 hours to burn it completely. Suppose they are burning at same rate. Find the time after which height of the first will be half of the second candle
Answer & Explanation
Answer : Option C 

Explanation : 


4 .
The side AB of a parallelogram ABCD is produced to E in such way that BE = AB. DE intersects BC at Q. The point Q divides BC in the ratio
Answer & Explanation
Answer : Option B 

Explanation : 


5 .
If sin$\theta$ + cos$\theta$ = m and sec$\theta$ + cosec$\theta$ = n, then find the value of n$m^2  1 \over 2$
Answer & Explanation
Answer : Option A 

Explanation : 


6 .
The ratio of number of boys to that of girls in a group becomes 2 : 1, when 15 girls leave. But, afterwards, when 45 boys also leave and the ratio becomes 1 : 5. In the beginning the number of boys was
Answer & Explanation
Answer : Option D 

Explanation : 

Let the original number of boys and girls be xand yrespectively.
Then,
$x \over y  15$ = $2 \over 1$
x = 2 y  30 ........... (i)
Again, $x  45 \over y  15$ = $1 \over 5$
5x 225 = y 15
5x= y 15 + 225
5(2y 30) = y+ 210 [From equation (i)]
10y 150 = y+ 210
10y y= 210 + 150
9y= 360
y = $360 \over 9$ = 40
Also, x = 2y  30 = 2 $\times$ 40  30 = 50
No.of boys = 50 
7 .
9 taps of same capacity fill up a water tank in 20 minutes. How many taps of the same capacity are required to fill up the same water tank in 18 minutes?
Answer & Explanation
Answer : Option A 

Explanation : 

Let the no.of taps be $M_2 $
$M_1$$D_1$ = $M_2$$D_2$
9 $\times$ 20 =$M_2$$\times$ 18
$M_2$ = $9 \times 20 \over 18$ = 10 pipes 
8 .
The pie chart given show the data on number of foreign collaborations approved with various countries. Some of these foreign collaborations are technical while others include foreign investment too. Study the pie chart and answer the questions below it
By how much did the number of foreign collaboration approved with A increase from 2013 to 2016?
Answer & Explanation
Answer : Option C 

Explanation : 

In 2013 collaboration with A = $64.8\over 3600$$\times$ 1200
= 216
In 2016 collaboration with A = $75.6\over 3600$$\times$ 1500
= 315
Required difference = 315  216 = 99 
9 .
The pie chart given show the data on number of foreign collaborations approved with various countries. Some of these foreign collaborations are technical while others include foreign investment too. Study the pie chart and answer the questions below it
What is the ratio of the number of foreign collaborations approved with F in 2013 to those in 2016?
Answer & Explanation
Answer : Option C 

Explanation : 

In 2013 = $50.4\over 3600$ $\times$ 1200 = 168
In 2016 = $43.2\over 3600$ $\times$ 1500 = 180$\times$$\times$ Required Ratio = 168 : 180 = 14 : 15 
10 .
The pie chart given show the data on number of foreign collaborations approved with various countries. Some of these foreign collaborations are technical while others include foreign investment too. Study the pie chart and answer the questions below it
By what percent did foreign collaborations approved with E change in 2016 with respect to 2013?
Answer & Explanation
Answer : Option B 

Explanation : 

In 2013 = $54 \over 360$ $\times$ 1200 = 180
In 2016 = $46.8 \over 360$ $\times$ 1500 = 195
Required change = $15 \over 180$ $\times$ 100
= 8 $1 \over 3$% increase 
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